Question

4(3X + 1\2)+(3X + 1)-3 = 0

Answer 1

$\displaystyle 4\Bigg(3x + \frac{1}{2}\Bigg) + \Bigg(3x + 1\Bigg) - 1 = 0 \\\\\\</p><p>\displaystyle 4\Bigg(3x + \frac{1}{2}\Bigg) + 3x+1-1 = 0 \\\\\\</p><p>\displaystyle 12x+2+3x=0 \\\\\\\</p><p>\displaystyle 15x+2=0 \\\\\\</p><p>\displaystyle 15x = -2 \\\\\\</p><p>\displaystylex \boxed{x=-\frac{2}{15}}$