Question

$\frac{135}{ {a}^{2} - 6a} \times \frac{a - 6}{3a + 9} - \frac{5a}{a + 3}$
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Answer 1

Ответ:

$\frac{15-5a}{a}$

Объяснение:

$\frac{135}{a^{2}-6a }$ × $\frac{a-6}{3a+9} -\frac{5a}{a+3}$

$\frac{135}{a(a-6)}$ × $\frac{a-6}{3(a+3)} -\frac{5a}{a+3}$

$\frac{45}{a}$ × $\frac{1}{a+3} -\frac{5a}{a+3}$

$\frac{45}{a(a+3)} -\frac{5a}{a+3}$

$\frac{45-5a^{2} }{a(a+3)}$

$\frac{5(9-a^{2})}{a(a+3)}$

$\frac{5(3-a)(3+a)}{a(a+3)}$

$\frac{15-5a}{a}$