Question

СРОЧНО НУЖНА ПОМОЩЬ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Ответ:

Объяснение:

$7.\\1.\sqrt{a^8} =a^4\\2.\sqrt[4]{a^8}=a^2\\ 3.\sqrt{\sqrt[4]{a^8} }=a\\ 4.\sqrt{\sqrt[8]{a^4} } =a^\frac{1}{2}. \\8.\\\sqrt[3]{5-2\sqrt{6} } *\sqrt[6]{49+20\sqrt{6} } = \sqrt[3]{5-2\sqrt{6} } *\sqrt[6]{25+20\sqrt{6} +24} =\\ = \sqrt[3]{5-2\sqrt{6} } *\sqrt[6]{5^2+2*5*2*\sqrt{6} +(2\sqrt{6})^2 }= \sqrt[3]{5-2\sqrt{6} } *\sqrt[6]{(5+2\sqrt{6} })^2 =\\ \sqrt[3]{5-2\sqrt{6} } * \sqrt[3]{5+2\sqrt{6} }=\sqrt[3]{(5-2\sqrt{6})*(5+2\sqrt{6}) } =\\=\sqrt[3]{5^2-(2\sqrt{6})^2 }= \sqrt{25-24}= 1.$