Question

Найти производную следующих функций:
у = 5х4 + 4х2 + 2х - 9
у = 3х4 + 3х8 – 2

Answer 1

$y = 5x4 + 4x2 + 2x - 9$

$y' = \frac{d}{dx} (5x4 + 4x2 + 2x - 9)$

$y' = \frac{d}{dx} (20x + 8x + 2x - 9)$

$y' = \frac{d}{dx} (30x - 9)$

$y' = \frac{d}{dx} (30x) - \frac{d}{dx} (9)$

$y' = 30 - 0$

$y' = 30$

________

$y = 3x4 + 3x8 - 2$

$y' = \frac{d}{dx} (3x4 + 3x8 - 2)$

$y' = \frac{d}{dx} (12x + 24x - 2)$

$y' = \frac{d}{dx} (36x - 2)$

$y' = \frac{d}{dx} (36x) - \frac{d}{dx} (2)$

$y' = 36 - 0$

$y' = 36$