Question

$\sqrt{3}-\sqrt{12} *cos^{2}\frac{29pi}{12}$

Answer 1

$\sqrt{3}*(1-\sqrt{4}*cos^2(\dfrac{29\pi}{12}))=\sqrt{3}*(1-2*cos^2(\dfrac{29\pi}{12}))=\\\\=-\sqrt{3}*cos(2*\dfrac{29\pi}{12})=-\sqrt{3}*cos(\dfrac{29\pi}{6})=-\sqrt{3}*cos(5\pi-\frac{\pi}{6})=\\\\=-\sqrt{3}*(-\frac{\sqrt{3} }{2})=3/2=1,5$

Answer 2

Ответ:

1.5

Объяснение: