Question

помогите пожалуйста!!!​

Answer 1

$1)2m+x-2y=2*3+5=11\\\\2)m(2y-x)=-m(x-2y)=-3*5=-15\\\\3)\frac{3(x-2y)}{m+2(2y-x)}=\frac{3(x-2y)}{m-2(x-2y)}=\frac{3*5}{3-2*5}=\frac{15}{-7}=-2\frac{1}{7}\\\\4)\frac{4}{m}+\frac{7}{x-2y}=\frac{4}{3}+\frac{7}{5}=\frac{20+21}{15}=\frac{41}{15}=2\frac{11}{15}$