Question

sin pi/4*cos pi/4-sin pi/3*cos pi/6

Answer 1

sin(π/4)·cos(π/4) - sin(π/3)·cos(π/6) = I

$\sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$

$\cos(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$

$\sin(\frac{\pi}{3}) = \frac{\sqrt{3}}{2}$

$\cos(\frac{\pi}{6}) = \frac{\sqrt{3}}{2}$

$I = \frac{\sqrt{2}}{2}\cdot\frac{\sqrt{2}}{2} -$

$- \frac{\sqrt{3}}{2}\cdot\frac{\sqrt{3}}{2} =$

$= \frac{2-3}{4} = -\frac{1}{4} = -0{,}25$