Question

Решите неравенство x-3/4^x-1 <=0

Answer 1

Ответ:

Объяснение:

x-3≤0

4^x-1>0

x≤3

x>0

x∈(0;3]

x-3≥0

4^x-1<0

x≥3

x<0 нет пересечений

Ответ: x∈(0;3]

Answer 2

Ответ:

$\dfrac{x-3}{4^{x}-1}\leq 0\ \ \ \Rightarrow \ \ \ \left\{\begin{array}{l}x-3\leq 0\\4^{x}-1>0\end{array}\right\ \ \ ili\ \ \ \left\{\begin{array}{l}x-3\geq 0\\4^{x}-1<0\end{array}\right\\\\\\\left\{\begin{array}{ccc}x\leq 3\\4^{x}>1\end{array}\right\ \ \ ili\ \ \ \left\{\begin{array}{ccc}x\geq 3\\4^{x}<1\end{array}\right$

$\left\{\begin{array}{ccc}x\leq 3\\x>0\end{array}\right\ \ \ ili\ \ \ \left\{\begin{array}{ccc}x\geq 3\\x<0\end{array}\right\\\\\\0<x\leq 3\ \ \ \ ili\ \ \ \ \ x\in \varnothing \\\\\\Otvet:\ \ x\in (\, 0\, ,\, 3\ ]\ .$