Question

100 БАЛЛОВ! При каких значениях переменных выражение не имеет смысла

Answer 1

Ответ:

$a)\ \ \dfrac{x^2-4}{(2x-1)(3x+7)}\ \ \to \ \ \left\{\begin{array}{l}2x-1\ne 0\\3x+7\ne 0\end{array}\right\ \ \left\{\begin{array}{ccc}x\ne \dfrac{1}{2}\\\ x\ne -\dfrac{7}{3} \end{array}\right$

$b)\ \ \dfrac{2xy+1}{(2x-1)(y+2)}\ \ \to \ \ \ \left\{\begin{array}{l}2x-1\ne 0\\y+2\ne 0\end{array}\right\ \ \left\{\begin{array}{l}x\ne \dfrac{1}{2}\\x\ne -2\end{array}\right$

$c)\ \ \dfrac{2x+y+3}{(x+3)(2y+1)}\ \ \to \ \ \ \left\{\begin{array}{l}x+3\ne 0\\2y+1\ne 0\end{array}\right\ \ \left\{\begin{array}{l}x\ne -3\\x\ne -\dfrac{1}{2}\end{array}\right$

$d)\ \ \dfrac{xy+x^2+3}{(x+2y)(2x-3y)}\ \ \to \ \ \ \left\{\begin{array}{l}x+2y\ne 0\\2x-3y\ne 0\end{array}\right\ \ \left\{\begin{array}{l}y\ne -\dfrac{x}{2}\\y\ne \dfrac{2x}{3}\end{array}\right$

$e)\ \ \dfrac{y^2+x+y-2}{(2x-5y)(x+3y)}\ \ \to \ \ \ \left\{\begin{array}{l}2x-5y\ne 0\\x+3y\ne 0\end{array}\right\ \ \left\{\begin{array}{l}y\ne \dfrac{2x}{5}\\y\ne -\dfrac{x}{3}\end{array}\right$

Answer 2

Ответ: приложено

Объяснение: