Question

помогите пожалуйста ,на листочке

Answer 1

Ответ:

$\dfrac{3xy-y^2}{x-y}-\dfrac{y\sqrt{y}}{\sqrt{x}-\sqrt{y}}-\dfrac{y\sqrt{x}}{\sqrt{x}+\sqrt{y}}=\\\\\\=\dfrac{3xy-y^2}{(\sqrt{x}-\sqrt{y})(\sqrt{x}+\sqrt{y})}-\dfrac{y\sqrt{y}}{\sqrt{x}-\sqrt{y}}-\dfrac{y\sqrt{x}}{\sqrt{x}+\sqrt{y}}=\\\\\\=\dfrac{3xy-y^2-y\sqrt{y}(\sqrt{x}+\sqrt{y})-y\sqrt{x}(\sqrt{x}-\sqrt{y})}{(\sqrt{x}-\sqrt{y})(\sqrt{x}+\sqrt{y})}=$

$=\dfrac{3xy-y^2-y\sqrt{xy}-y^2-xy+y\sqrt{xy}}{(\sqrt{x}-\sqrt{y})(\sqrt{x}+\sqrt{y})}=\dfrac{2xy-2y^2}{x-y}=\dfrac{2y(x-y)}{x-y} =2y$