Question

Пожалуйста, вычислите логарифм

Answer 1

log(2) (log(4) 256 ) = log(2) (log(4) 4^4) = log(2) 4 = log(2) 2^2 = 2

log (∛2) 8 = 3 log(2) 2^3 = 9

2 - 9 = -7

log(a^n) b^m = m/n log(a) b

Answer 2

$log_{2}log_{4}256-log_{\sqrt[3]{2}}8=log_{2}log_{4}4^{4}-log_{(\sqrt[3]{2})^{3}}(2^{3})^{3}=log_{2}4-log_{2}2^{9}=2-9=-7\\\\Otvet:\boxed{-7}$