Question

СРОЧНО, ПОМОГИТЕ, ПОЖАЛУЙСТА

Answer 1

1) ctg(π-3)*cos(π/2-3)-sin(3π/2-3)=-ctg3*sin3+cos3=-cos3+cos3=0

2) sin(5π/6+α)*cos(π/3+α)-cos(5π/6+α)*sin(π/3+α)=sin(5π/6+α-(π/3+α))=

sin(5π/6+α-π/3-α)=sin(5π/6-2π/6)=sin(3π/6)=sinπ/2=1 Доказано.