Question

Решите пожалуйста :)



1)4х^2-3,6х=0

2)х^2+5х=0

3)7х^2-17=0

4)х^2-81=0

Answer 1

Объяснение:

1)

$1) {4x}^{2} - 3.6x = 0 \\ x (4x - 3.6) = 0 \\ 1)x = 0 \\2)4x - 3.6 = 0 \\ 4x = 3.6 \\ x = 0.9$

2)

${x}^{2} + 5x = 0 \\ x(x + 5) = 0 \\1) x = 0 \\2) x + 5 = 0 \\ x = - 5$