Question

2 вг, 3 вг,



больше Символов больше БОЛЬШЕЕЕЕ

Answer 1

Ответ:

в решении

Объяснение:

$2)v) {4}^{ - 2} \div \frac{ - 1}{64} = \frac{1}{ {4}^{2} } \times ( - 64) = \frac{1}{16} \times( - 64) = \frac{ - 64}{16} = - 4$

$2)g)(0.008) {}^{0} \div {( - 3)}^{ - 3} = 1 \div ( - \frac{1}{ {3}^{3} } ) = 1 \times ( - 27) = - 27$

$3)v)(0.2cd {}^{ - 3} ) {}^{ - 2} = (\frac{1 \times c}{5 \times {d}^{3} } ) {}^{ - 2} = ( \frac{5 {d}^{3} }{c} ) {}^{2} = \frac{25 {d}^{6} }{ {c}^{2} }$

$3)g)(8 {p}^{ - 3} {k}^{2} \times 0.5pk {}^{ - 2}) {}^{ - 3} = ( \frac{8 {k}^{2} }{ {p}^{3} } \times \frac{1 \times p}{2 \times {k}^{2} } ) {}^{ - 3} = (\frac{4}{ {p}^{2} } ) {}^{ - 3} = ( \frac{ {p}^{2} }{4} ) {}^{3} = \frac{ {p}^{6} }{ {4}^{3} } = \frac{ {p}^{6} }{64}$