Question

Решите пожалуйста!!!!!!!

Answer 1

Ответ:

в решении

Объяснение:

$\frac{14 {a}^{3} {b}^{5} }{21 {a}^{4}b } = \frac{14 {b}^{4} }{21a}=\frac{2 {b}^{4} }{ 3a}\\ \frac{ab - b}{ {b}^{2} } = \frac{b(a - 1)}{b \times b} = \frac{a - 1}{b}$

$\frac{ {m}^{3} - 5 {m}^{2}n }{5 {n}^{3} - m {n}^{2} } = \frac{ {m}^{2}(m - 5n) }{ {n}^{2}(5n - m) } = \frac{ - {m}^{2}(5n - m) }{ {n}^{2} (5n - m)} = - \frac{ {m}^{2} }{ {n}^{2} }$

$\frac{9 {a}^{2} - 16 }{3a + 4} = \frac{(3a + 4)(3a - 4)}{(3a + 4)} =3a - 4$

Answer 2

Объяснение:

$\frac{14 {a}^{3} {b}^{5} }{21 {a}^{4} b} = \frac{2 {b}^{4} }{3a}$

$\frac{ {m}^{3} - 5 {m}^{2} n}{5 {n}^{3} - m{ n}^{2} } = \frac{ {m}^{2}( m -5n) }{ - {n}^{2} (m - 5n)} = - \frac{ {m}^{2} }{ {n}^{2} }$

$\frac{ab - b}{ {b}^{2} } = \frac{b(a - 1)}{ {b}^{2} } = \frac{ a- 1}{b}$

$\frac{9 {a}^{2} - 16}{3a + 4} = \frac{(3a + 4)(3a - 4)}{3a + 4} = 3a - 4$