Question

ПОМОГИТЕ ПОЖАЛУЙСТА ПО АЛГЕБРЕ

Answer 1

Ответ:

Объяснение:

1)

(a-2b)²=a²-2ab+4b²

(3x-y)(3x+y)=9x²-y²

y²-49=(y-7)(y+7)

2)

(5a-2b)²=25a²-20ab+4b²

(4x³+3y)(3y-4x³)=9x²-16$x^{6}$

16m²-$n^{16}$=(4m-$n^{8}$)(4m+

(x+2)(x²-4x+4)=x³+8

3)

$\frac{25x^{2}+10x+1}{25x^{2}-1} =\frac{(5x+1)^{2}}{(5x-1)(5x+1)} =\frac{5x+1}{5x-1}$

$\frac{x^{2}-16}{3x+12} =\frac{(x-4)(x+4)}{3(x+4)}=\frac{x-4}{3}$

$\frac{a^{3}-27}{a^{2}+3a-9} =\frac{(a-3)(a^{2}+3a-9)}{a^{2}+3a-9}=a-3$

$\frac{a^{2}+4ab+4b^{2}}{a^{2}-4b^{2}} =\frac{(a+2b)^{2}}{(a-2b)(a+2b)} =\frac{a+2b}{a-2b}$

$\frac{x^{2}-25}{2x+10} =\frac{(x-5)(x+5)}{2(x+5)} =\frac{(x-5)}{2}$

$\frac{b^{2}-49}{49-14b+b^{2}} =\frac{(b-7)(b+7}{(7-b)^{2}}=\frac{-b-7}{7-b}$