Question

Найдите корень уравнения.
0,1x^2 - 0,6x + 0,9 = 0
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Answer 1

$\displaystyle 0,1x^2 - 0,6x + 0,9 = 0\;\;\;\;\; \boxed{a=0.1\;\;\;\;b=-0.6\;\;\;\;c=0.9}\\\\D=(-0.6)^2-4*0.1*0.9=(-\frac{3}{5} )^2-4*0.1*0.9=(-\frac{3}{5} )^2-0.36=\frac{9}{25} -\frac{9}{25}=0 \\\\x=\frac{-(-0.6)}{2*0.1}=\frac{0.6}{2*0.1} =\frac{6}{2} =3\\\\\\ \boxed{x=3}$