Question

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Answer 1

Объяснение:

$\frac{6}{7} :(2-\frac{5}{7} )=\frac{6}{7}:1\frac{2}{7} =\frac{6}{7}:\frac{9}{7} =\frac{6}{7}*\frac{7}{9}=\frac{2}{3} \notin \mathbb Z (\in \mathbb Q).\\ (\frac{3}{2}-\frac{2}{3})*\frac{6}{5}=\frac{3*3-2*2}{2*3} *\frac{6}{5} =\frac{9-4}{6} *\frac{6}{5}=\frac{5}{6}*\frac{6}{5} =1 \notin \mathbb Q (\in\mathbb N).\\\frac{7}{15} *\frac{5}{7} *\frac{6}{5}=\frac{7*5*6}{15*7*5} =\frac{2}{5} \notin\mathbb N(\in\mathbb Q).$

$\frac{4}{7} *\frac{14}{5}:\frac{2}{5} =\frac{4}{7}*\frac{14}{5}*\frac{5}{2} =\frac{4*14*5}{7*5*2}=4\in\mathbb N .$