Question

{X+y^2=2
{2y^2+x^2=3
Решить

Answer 1

Ответ:

{х+у^2=2

{2у^2+х^2=3

{х=2-у^2

{2у^2+х^2=3

2у^2+(2-у^2)^2=3

у=-1

у=1

х=2-(-1)^2

у=2-1^2

х=1

х=1

(х 1 , у 1) =(1; -1)

(х 2 ; у 2) = (1;1)