Question

Номер один !!!!!! Помогите дам 24 балла !!!!! Срочно ?!!!!!

Answer 1

$\displaystyle \frac{15a^2-10ab}{3ab-2b^2}=\frac{5a(3a-2b)}{b(3a-2b)}=\frac{5a}{b} \\\\\\a=-2\;\;\;\;\;b=-0.1\\\\\\\frac{5*(-2)}{-0.1} =\frac{5*2}{0.1} =\frac{10}{0.1} =\boxed{100}$

Answer 2

$\frac{15a^{2}-10ab}{3ab-2b^{2}}=\frac{5a(3a-2b)}{b(3a-2b)}=\frac{5a}{b}\\\\a=-2;b=-0,1\Rightarrow \frac{5a}{b} =\frac{5*(-2)}{-0,1}=\frac{-10}{-0,1}=100\\\\Otvet:\boxed{100}$