Question

за 7 класс, карантин не пошёл мне на пользу. спасибо.​

Answer 1

6/(3*(х+у))  +  8х/(4*(х²-у²))=

2/(х+у)  +  2х/((х-у)(х+у))= разность квадратов

(2(х-у) + 2х)/((х-у)(х+у))=

(2х-2у+2х)/((х-у)(х+у))=

(4х-2у)/(х²-у²) или 2(2х-у)/(х²-у²).

Answer 2

$\frac{6}{3x+3y}+ \frac{8x}{4x^{2}-4y^{2}} = \frac{6}{3*(x+y)}+ \frac{8x}{4*(x-y)(x+y)} = \frac{6*4*(x-y)+8x*3}{12(x-y)(x+y)} = \frac{24x-24y+24x}{12(x-y)(x+y)} =$

$=\frac{48x-24y}{12(x-y)(x+y)} = \frac{24*(2x-y)}{12(x-y)(x+y)} = \frac{2*(2x-y)}{(x-y)(x+y)}$