Question

Х² -3х -10 > 0 Помогите плиз

Answer 1

Ответ:

x>5; x>-2

Объяснение:

x^2 - 3x -10 >0

(x-5)(x+2)>0

x>5; x>-2

Answer 2

$x^2 - 3x - 10 > 0\\\\D = b^2 - 4ac = (-3)^2 - 4 * 1 * (-10) = 9 + 40 = 49\\\sqrt{D} = 7$

$x = \frac{-b б \sqrt{D} }{2a}\\\\x_1 = \frac{3 + 7}{2} = 5\\x_2 = \frac{3 - 7}{2} = -2$

x ∈ (-∞; -2)U(5; +∞)