Question

помогите пожалуйста.......

Answer 1

$\sqrt[4]{2}\cdot\frac{\sqrt[4]{2}\left(\sqrt{8+2\sqrt{15}}-\sqrt{7-2\sqrt{10}}\right)}{\sqrt{2}\sqrt{5+2\sqrt{6}}\right)}=\frac{\sqrt{(\sqrt{5}+\sqrt{3})^2}-\sqrt{(\sqrt{5}-\sqrt{2})^2}}{\sqrt{(\sqrt{3}+\sqrt{2})^2}}=\frac{|\sqrt{5}+\sqrt{3}|-|\sqrt{5}-\sqrt{2}|}{|\sqrt{3}+\sqrt{2}|}=$

$=\frac{\sqrt{5}+\sqrt{3}-\sqrt{5}+\sqrt{2}}{\sqrt{3}+\sqrt{2}}=\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}}=1$

Ответ: 1