Question

Помогите пожалуйста!

Answer 1

Ответ:

$f(x)=\left\{\begin{array}{l}2x+5\ ,\ -2\leq x\leq 0\ ,\\(x-1)^2+4\ ,\ 0<x\leq 4\ .\end{array}\right\\\\\\f(-2)=(2x+5)\, \Big|_{x=-2}=2\cdot (-2)+5=1\\\\f(x)=(2x+5)\, \Big|_{x=0}=2\cdot 0+5=5\\\\f(1)=(x-1)^2+4\, \Big|_{x=0}=(1-1)^2+4=4\\\\f(3)=(x-1)^2+4\, \Big|_{x=3}=(3-1)^2+4=2^2+4=8$