Question

Алгебра срочно помогите .​

Answer 1

Объяснение:

$1)\ 100^{34}:100^{32}:100^x=100^{34-32}:100^x=100^2:100^x=100^{2-x}.\ \ \ \ \Rightarrow\\2-x=0\\x=2.\\2)\ (-40)^{50}:(-40)^x:(-40)^{21}=(-40)^{50-x}:(-40)^{21}=\\=(-40)^{50-x-21}=(-40)^{29-x}\ \ \ \ \Rightarrow\\29-x=0\\x=29.\\3)\ (\frac{1}{6})^{42}*(\frac{1}{6})^9:(\frac{1}{6} )^x=(\frac{1}{6})^{42+9}:(\frac{1}{6})^x=(\frac{1}{6})^{51-x}\ \ \ \ \Rightarrow\\51-x=0\\x=51.\\4)\ (-9,3)^x:(-9,3)^{23}:(-9,3)^{48}=(-9,3)^{x-23-48}=(-9,3)^{x-71}\ \ \ \ \Rightarrow\\x-71=0\\x=71.$