Question

решите систему у-3х=1 х^2-2ху+у^2=9

Answer 1

$left { {{y=1+3x} atop {(x-y)^2-3^2=0}} right. \ left { {{y=1+3x} atop {(x-y-3)(x-y+3)=0}} right. \ left { {{y=1+3x} atop {(x-1-3x-3)(x-1-3x+3)=0}} right. \ left { {{y=1+3x} atop {(-2x-4)(-2x+2)=0}} right. \ -2x-4 = 0 \ -2x=4 \ x_{1}=-2 \ -2x+2=0 \ x_{2} =1 \ left { {{y=-5} atop {x=-2}} right. left { {{y=4} atop {x=1}} right.$
Ответ: (-2;-5),(1;4)