Question

Помогите номер 1.96 срочно даю 20 баллов
Нужно 1 и 4 решить

Answer 1

$1)\ \ f(x)=\dfrac{3}{2x-1}\ \ ,\ \ \ ODZ:\ x\ne \dfrac{1}{2}\\\\y=\dfrac{3}{2x-1}\ \ \to \ \ 2x-1=\dfrac{3}{y}\ \ ,\ \ 2x=\dfrac{3}{y}+1\ \ ,\ \ x=\dfrac{3}{2y}+\dfrac{1}{2}\ \ ,\ \ x=\dfrac{3+y}{2y}\\\\\\\boxed {\ y=\dfrac{3+x}{2x}\ }\ \ \ obratnaya\ fynkciya$

$4)\ \ y=\sqrt{25-x^2}\ \ ,\ \ 0\leq x\leq 5\\\\y^2=25-x^2\ \ \to \ \ x^2=25-y^2\ \ ,\ \ \sqrt{x^2}=\sqrt{25-y^2}\ \ \to \ \ |\, x\, |=\sqrt{25-y^2}\ ,\\\\x\geq 0\ \ \to \ \ |\, x\, |=x\ \ \to \ \ x=\sqrt{25-y^2}\ \ ,\ \ -5\leq y\leq 5\\\\\boxed {\ y=\sqrt{25-x^2}\ ,\ -5\leq x\leq 5\ }$