Question

​Помогите пожалуйста
и там еще продолжение 3.9
$3) {(ax)}^{41} \times {(ax)}^{12 } \div {(ax)}^{33} =$
$4) {(3z)}^{56} \div { (3z)}^{51} \times (3z) =$
$(5)( \frac{c}{5} ) {}^{66} \div (\frac{c}{5} ) {}^{62} \times (\frac{c}{5} ) {}^{3} =$
$6) {( - kt)}^{49} \div {( - kt)}^{39} \times {( - kt)}^{10 } =$

Answer 1

Объяснение:

$3)\ (ax)^{41}*(ax)^{12}:(ax)^{33}=(ax)^{41+12-33}=(ax)^{20}.\\4)\ (3z){56}:(3z)^{51}*(3z)=(3z)^{56-51+1}=(3z)^6.\\5)\ (\frac{c}{5})^{66}:(\frac{c}{5})^{62}*(\frac{c}{5})^3= (\frac{c}{5})^{66-62+3}=(\frac{c}{5})^7.\\6)\ (-kt)^{49}:(-kt)^{39}*(-kt)^{10}=(-kt)^{49-39+10}=(-kt)^{20}=(kt)^{20}.$

$3.9.\\1)\ a^{100}:a^{89}*a^2=a^{100-89+2}=a^{13}.\\2)\ b^{98}:b^{88}*b^{15}=b^{98-88+15}=b^{25}.$