Question

ПОМОГИТЕ РЕШИТЬ УРАВНЕНИЕ

Answer 1

$\displaystyle\\x^2-(2p+1)x+(p^2+p-2)=0\\\\D=b^2-4ac=(2p+1)^2-4*1*(p^2+p-2)=4p^2+4p+1-4p^2-4p+8=\\\\=9\\\\\sqrt{D}=\sqrt{9}=3\\\\x_1=\frac{2p+1+3}{2}=p+2\\\\x_2=\frac{2p+1-3}{2}=p-1$