Question

Срочно пожалуйста!!!!​

Answer 1

$(3a^{9}b^{3})^{2}:(-4a^{4}b)^{4}=\frac{9a^{18}b^{6}}{256a^{16}b^{4}}=\frac{9}{256}a^{18-16}b^{6-4}=\frac{9}{256}a^{2}b^{2}\\\\a=-\frac{5}{9};b=-16\\\\\frac{9}{256}*(-\frac{5}{9})^{2}*(-16)^{2}=\frac{9}{256}*\frac{25}{81}*256=\frac{25}{9}=2\frac{7}{9}\\\\Otvet:\boxed{2\frac{7}{9}}$