Question

Решите пожалуйста!!!

Answer 1

$\Big(3\dfrac{1}{8}-2\dfrac{5}{12}\Big)\cdot (-1\dfrac{3}{17}\Big)=\Big(\dfrac{25}{8} -\dfrac{29}{12}\Big)\cdot \Big(-\dfrac{20}{17}\Big)=-\dfrac{3\cdot 25-2\cdot 29}{24}\cdot \dfrac{20}{17}=\\\\\\=-\dfrac{17}{24}\cdot \dfrac{20}{17}=-\dfrac{20}{24}=-\dfrac{5}{6}$