Question

3/x+2-(3/2-x)=2/x^2-4

Answer 1

$frac{3}{x+2}- frac{3}{2-x}= frac{2}{ x^{2} -4}$
$frac{3}{x+2}+ frac{3}{x-2}= frac{2}{ (x -2)(x+2)}$
$3(x-2)+ 3(x+2)= 2$
$3x-6+ 3x+6= 2$
$6x= 2$
$x= frac{1}{3}$

Answer 2

3/(x+2)-3/(2-x)=2/(x^2-4)
3(x-2)/(x^2-4)+3(x+2)/(x^2-4)=2/(x^2-4)
x<> -2 2
3(x-2)+3(x+2)=2
3x-6+3x+6=2
6x=2
x=1/3