Question

Пж срочна............................ ​

Answer 1

$1)0,(3)=\frac{3}{9}=\frac{1}{3}\\\\2)0,2(5)=\frac{25-2}{90}=\frac{23}{90}\\\\3)7,(36)=7\frac{36}{99}=7\frac{4}{11}\\\\4)7,2(23)=7\frac{223-2}{990}=7\frac{221}{990}$

$5)4,2(25)=4\frac{225-2}{990}=4\frac{223}{990}\\\\6)1,0(2)=1\frac{2}{90}=1\frac{1}{45} \\\\7)10,21(4)=10\frac{214-21}{900} =10\frac{193}{900}$

$8)-2,1(12)=-(2\frac{112-1}{990})=-2\frac{111}{990}=-2\frac{37}{330}\\\\9)0,(312)=\frac{312}{999}=\frac{104}{333}\\\\10)0,0(2)=\frac{2}{90}=\frac{1}{45}$