Question

sin(x+3/2П)-cos(4(x-3/2П))=0

Answer 1

-cosx-cos(4x-6П)=-cosx-cos4x=-(cosx+cos4x)=-2cos5x/2cos3x/2=0
cos5x/2=0,5/2x=П/2+2Пn,x=П/5+4П/5n
сщы3ч/2=0б3ч/2=П/2+2Пn,x=П/3+4П/3n

Answer 2

Спасибо!