Question

помогите с упр 10,11​

Answer 1

$\sqrt{16 \times 121} = \sqrt{16} \times \sqrt{121} = 4 \times 11 = 44$

$\sqrt{49 \times 25} = \sqrt{49} \times \sqrt{25} = 7 \times 5 = 35$

$\sqrt{9 \times 0.36 \times 16} = \sqrt{9} \times \sqrt{0.36} \times \sqrt{16} = 3 \times 0.6 \times 4 = 7.2$

$\sqrt{ \frac{36}{169} } = \frac{ \sqrt{36} }{ \sqrt{169} } = \frac{6}{13}$

$\sqrt{ \frac{1}{81} \times \frac{16}{25} } = \frac{1}{ \sqrt{81} } \times \frac{ \sqrt{16} }{ \sqrt{25} } = \frac{1}{9} \times \frac{4}{5} = \frac{4}{45}$

$\sqrt{17 {}^{2} \times 3 {}^{2} } = \sqrt{17 {}^{2} } \times \sqrt{ {3}^{2} } = 17 \times 3 = 51$

$\sqrt{ \frac{1}{17} } \times \sqrt{ \frac{17}{49} } = \sqrt{ \frac{17}{17 \times 49} } = \frac{1}{ \sqrt{49} } = \frac{1}{7}$

$\sqrt{3} \times \sqrt{48} = \sqrt{3 \times 3 \times 4 \times 4} = 3 \times 4 = 12$

$\sqrt{48 \times 27} = \sqrt{16 \times 3 \times 3 \times 9} = 4 \times 3 \times 3 = 36$

$\sqrt{50 \times 72} = \sqrt{25 \times 2 \times 2 \times 4 \times 9} = 5 \times 2 \times 2 \times 3 = 60$

$\sqrt{98 \times 18} = \sqrt{49 \times 2 \times 2 \times 9} = 7 \times 2 \times 3 = 42$

$\sqrt{75 \times 243} = \sqrt{25 \times 3 \times 3 \times 81} = 5 \times 3 \times 9 = 135$

$\sqrt{13 {}^{2} - {12}^{2} } = \sqrt{(13 - 12)(13 + 12)} = \sqrt{25} = 5$

$\sqrt{ {17}^{2} - {8}^{2} } = \sqrt{(17 - 8)(17 + 8)} = \sqrt{9 \times 25} = 3 \times 5 = 15$

$\sqrt{25 {}^{2} - {24}^{2} } = \sqrt{(25 - 24)(25 + 24)} = \sqrt{49} = 7$

$\sqrt{ {117}^{2} - {108}^{2} } = \sqrt{(117 - 108)(117 + 108)} = \sqrt{9 \times 225} = 3 \times 15 = 45$