Question

Объясните, пж, как решать.

Answer 1

Ответ: 2; - 11/5

5) 4log1/2 (3) -3/2*log1/2 (27)-2log1/2 (6) = 2log1/2 (3) +log1/2 (6^-2) = log2^-1 (3^2* 1 / 1/2^2*3^2) = log2^-1 (2^-2) = 2

6) 2/3 *log10 (0.001) + log10 (3√1000Қ - 3/5 * log10 (√10000) = /3*(-3) + 1 - 3/5 * log10 (10^2) = -1 - 6/5 = - 11/5