Question

Помогите пожалуйста...

Answer 1

$\frac{2 \times ( - 1) - \frac{1}{3} }{ - 1 - 3 \times \frac{1}{3} }$

$\frac{ - 2 - \frac{1}{3} }{ - 1 - 1}$

$\frac { - \frac {7}{3} }{ - 2}$

$\frac{ \frac{7}{3} }{2}$

$\frac{7}{6} = 1 \frac{1}{6}$

Answer 2

$\frac{2x-y}{x-3y} =\frac{2*(-1)-\frac{1}{3}}{-1-3*\frac{1}{3}}=\frac{-2-\frac{1}{3}}{-1-1} =\frac{-2\frac{1}{3}}{-2}=\frac{-\frac{7}{3}}{-2}=\frac{7}{3} *\frac{1}{2}=\frac{7}{6}=1\frac{1}{6}\\\\Otvet:\boxed{1\frac{1}{6}}$