Question

8 класс. Даю 35 баллов за один пример: упростить

Answer 1

$\frac{2}{x-4}- \frac{x+8}{x^2+16} -\frac{1}{x} =\frac{2x(x^2+16)-x(x-4)(x+8)-(x-4)(x^2+16)}{x(x-4)(x^2+16)} =\\\\=\frac{2x^3+32x-x(x^2-4x+8x-32)-(x^3-4x^2+16x-64)}{x(x-4)(x^2+16)} =\\\\=\frac{2x^3+32x-x^3+4x^2-8x^2+32x-x^3+4x^2-16x+64}{x(x-4)(x^2+16)} =\\\\=\frac{48x-64}{x(x-4)(x^2+16)}$