Question

Найти tg a, если 6cos^2a+sina-5=0 и -п/2<a<0

Answer 1

6-6sin^2x+sinx-5=0
6sin^2x-sinx-1=0
a=sinx
6a^2-a-1=0
a1=1/2,sinx=1/2,x=-П/6
сosx=$sqrt{3}$/2
tgx=tex] sqrt{3} [/tex]/3
a2=-1/3,sinx=-1/3
cosx=2$sqrt{2}$/3
tgx=-$sqrt{2}$/4