Question

Помогите с № 242, 243

Answer 1

Ответ:

$1.242a)\sqrt{36a^2b},a>0\\\sqrt{36a^2b}=6a\sqrt{b} \\\\b)\sqrt{32m^6n^7},m\leq 0\\\sqrt{32m^6n^7}=-4m^3n^3\sqrt{2n}\\\\c)\sqrt{1,21x^5y^7},x<0,y<0 \\ \sqrt{1,21x^5y^7}=\sqrt{1,21x^4*(-x)*y^6*(-y)}=1,1x^2(-y)^3\sqrt{xy}=-1,1x^2y^3\sqrt{xy}\\ \\\\1.243\\a)\sqrt{2x^3}=x\sqrt{2x}(x^3\geq0;x\geq 0) \\ \\b)\sqrt{-y^3}=\sqrt{-y*y^2}=-y\sqrt{-y}(-y^3\geq 0;y\leq 0)\\\\c)\sqrt{a^5b^4}=a^2b^2\sqrt{a}(a^5\geq 0;a\geq 0)$