Question

помогите!! я 2 вариант. даю 30 баллов. ​

Answer 1

Ответ:

1. Mr(CuO) = Ar(Cu) + Ar(O) = 64+16 = 80

  Mr(HBr) = Ar(H) + Ar(Br) = 1+80 = 81

Mr(AlPO4) = Ar(Al) + Ar(P) + Ar(O)*4 = 27 + 31+16*4 = 122

2. M(FeO )= 56 + 16 = 72 g/mol

W(Fe) = M(Fe) / M(FeO) * 100% = 56 / 72 * 100% = 77.78%

W(O) = M(O) / M(FeO) = 16 / 72 * 100% = 22.22 %

Объяснение: