Question

Даю 60 баллов пожалуйста

Answer 1

Ответ:

$\frac{x}{2} +\frac{y}{3} =\frac{3x}{3*2} +\frac{2*y}{2*3}=\frac{3x+2y}{6}$

$\frac{c}{4} -\frac{d}{12}=\frac{3c}{3*4}-\frac{d}{12}=\frac{3c-d}{12}$

$\frac{p}{q} +\frac{q}{p} =\frac{p^2}{p*q} +\frac{q^2}{pq}=\frac{p^2+q^2}{pq}$

$\frac{a}{b}-\frac{b^2}{a} =\frac{a^2}{ab} -\frac{b^3}{ab} =\frac{a^2-b^3}{ab}$

$\frac{2}{2x} -\frac{3}{3x} =\frac{1}{x} -\frac{1}{x} =\frac{1-1}{x} =0$

$\frac{a}{5c} +\frac{3a}{4c} =\frac{4a}{4*5c} +\frac{5*3a}{5*4c}=\frac{4a+15a}{20c} =\frac{19a}{20c}$

$\frac{5x}{8y} +\frac{x}{4y} =\frac{5x}{8y}+\frac{2x}{2*4y}=\frac{5x+2x}{8y}=\frac{7x}{8y}$

$\frac{17y}{24c} -\frac{25c}{36y}= \frac{3*17y}{3*24c} -\frac{2*25c}{2*36y}=\frac{51y-50y}{72c} =\frac{y}{72c}$

$\frac{5a}{18b}-\frac{7a}{45b}= \frac{5*5a}{*518b}-\frac{2*7a}{2*45b} =\frac{25b-14b}{90b}=\frac{11a}{90b}$

Пошаговое объяснение: