Question

3а+1/9а-6а+1 и а-2/9а²-1

Answer 1

Ответ:

1)

$3\alpha + \frac{1}{9} \alpha - 6\alpha +1$

$\frac{3\alpha }{1} + \frac{\alpha }{9} - \frac{6\alpha }{1} +1$

$\frac{9*3\alpha }{9*1} + \frac{\alpha }{9} - \frac{9*6\alpha }{9*1} + 1$

$\frac{27\alpha }{9} + \frac{\alpha }{9} - \frac{54\alpha }{9} +1$

$\frac{27\alpha + \alpha - 54 \alpha }{9} +1$

$\frac{-26\alpha }{9} +1 = -\frac{26}{9} \alpha +1$

2)

$\alpha - \frac{2}{9} \alpha ^{2} - 1$

$\frac{1}{9} * (9\alpha - 2\alpha ^{2} -9)$

$\frac{1}{9} * ( - 2\alpha ^{2} + 9\alpha -9)$

$\frac{1}{9} * (-2\alpha ^{2} + 6\alpha + 3\alpha -9)$

$\frac{1}{9} * (-2\alpha *(\alpha -3) +3 (\alpha -3))$

$\frac{1}{9} * (-(\alpha -3)*(2\alpha -3))= - \frac{1}{9} *(\alpha -3)*(2\alpha -3)$

Пошаговое объяснение: