Question

help me..................aaa

Answer 1

Ответ:

$x=\pm\sqrt2$

Объяснение:

$\displaystyle ( \frac13)^{5x^2+14}=(\frac19)^{x^2+10}\\\\(\frac13)^{5x^2+14}=((\frac13)^2)^{x^2+10}\\\\(\frac13)^{5x^2+14}=(\frac13)^{2x^2+20}\\\\\log_{\frac13}(\frac13)^{5x^2+14}=\log_{\frac13}(\frac13)^{2x^2+20}\\\\5x^2+14=2x^2+20\\\\5x^2-2x^2=20-14\\\\3x^2=6\\\\x^2=2\\\\x=\pm\sqrt2$

Answer 2

$(\frac{1}{3})^{5x^{2}+14 }=(\frac{1}{9})^{x^{2}+10}\\\\(\frac{1}{3})^{5x^{2}+14 }=(\frac{1}{3})^{2x^{2}+20}\\\\5x^{2}+14=2x^{2}+20\\\\3x^{2}=6\\\\x^{2}=2\\\\x_{1}=\sqrt{2}\\\\x_{2}=-\sqrt{2}$