Question

(8+3I)-(4+2I)=
(1+I)+(2-I)=

Answer 1

Ответ:

1) (8+3i) - (4+2i) = (8 - 4) + (3 - 2)·i = 4+i

2) (1+i) + (2-i) = (1 + 2) + (1 + (-1))·i = 3