Question

the frequency of the rotor of a helicopter is 1800 cycles/min, calculate the period of its rotor in seconds, if the rotor arm is 3 m long, find the tangential speed of a point at the far end of the arm. (Take p to be 3)

Answer 1

Ответ:

The angular speed of rotation of the screw w = 2p * n / t = (2p * 1800/3) = 62.8 s ^ -1