Question

Помогите время ограничено а то мене 2 поставят (3х – 2) – (х – 1) = 10 2(х – 1) – 4 = 6(х + 2) 12х + 4 = 2(4х – 2)
6(х – 3) = 12 3х + (2х – 1) = 10

Answer 1

Первый

$(3x - 2) - (x - 1) = 10$

$3x - 2 - x + 1 = 10$

$2x - 1 = 10$

$2x = 10 + 1$

$2x = 11$

$x = \frac{11}{2}$

Второй

$2(x - 1) - 4 = 6(x + 2)$

$2x - 2 - 4 = 6x + 12$

$2x - 6 = 6x + 12$

$2x - 6x = 12 + 6$

$- 4x = 18$

$x = - \frac{9}{2}$

Третье

$12x + 4 = 2(4x - 2)$

$12x + 4 = 8x - 4$

$12x - 8x = - 4 - 4$

$4x = - 8$

$x = - 2$

Четвёртое

$6(x - 3) = 12$

$x - 3 = 2$

$x = 2 + 3$

$x = 5$

Пятое

$3x + (2x - 1) = 10$

$3x + 2x - 1 = 10$

$5x - 1 = 10$

$5x = 10 + 1$

$5x = 11$

$x = \frac{11}{5}$

Фух держи