Question

Помогите:1/3 log 3(2x+1)=1

 

Answer 1

$displaystyle frac{1}{3}log_3(2x+1)=1$

$displaystyle ODZ: 2x+1 textgreater 0$

$displaystyle x textgreater - frac{1}{2}$

$displaystyle log_3(2x+1)=3 2x+1=3^3 2x+1=27 2x=26 x=13$