Question

25^(2x+6)+16*4^(2x+4)=20*10^(2x+5)

Answer 1

$25^{2x+6} +16*4^{2x+4} =20*10^{2x+5}$

$25^{2x+6} +4^{2} *4^{2x+4} =2*10^{1} *10^{2x+5}$

$5^{4x+12} -2*10^{2x+6}+2^{4x+12} =0$

$(5^{2x+6} -2^{2x+6} )^{2} =0$

$5^{2x+6} -2^{2x+6} =0$

$5^{2x+6} =2^{2x+6}|:2^{2x+6}$

$(\frac{5}{2})^{2x+6}=1$

$2x+6=0$

$x=-3$

Ответ: $x=-3$