Question

Sinx =√2\2, x[-π;π\2]

Answer 1

Ответ:

$\displaystyle \frac\pi4$

Объяснение:

$\displaystyle\sin x = н\sqrt2\\\left [ {{x=\frac14(\pi+8\pi n),n\in\mathbb{Z}} \atop {x=\frac14(-\pi+8\pi n),n\in\mathbb{Z}}} \right.$